1[3(5+a)-2]=a+5

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Solution for 1[3(5+a)-2]=a+5 equation:


Simplifying
1[3(5 + a) + -2] = a + 5
1[(5 * 3 + a * 3) + -2] = a + 5
1[(15 + 3a) + -2] = a + 5

Reorder the terms:
1[15 + -2 + 3a] = a + 5

Combine like terms: 15 + -2 = 13
1[13 + 3a] = a + 5
[13 * 1 + 3a * 1] = a + 5
[13 + 3a] = a + 5

Reorder the terms:
13 + 3a = 5 + a

Solving
13 + 3a = 5 + a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1a' to each side of the equation.
13 + 3a + -1a = 5 + a + -1a

Combine like terms: 3a + -1a = 2a
13 + 2a = 5 + a + -1a

Combine like terms: a + -1a = 0
13 + 2a = 5 + 0
13 + 2a = 5

Add '-13' to each side of the equation.
13 + -13 + 2a = 5 + -13

Combine like terms: 13 + -13 = 0
0 + 2a = 5 + -13
2a = 5 + -13

Combine like terms: 5 + -13 = -8
2a = -8

Divide each side by '2'.
a = -4

Simplifying
a = -4

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